Prove that equal chords of a circle substance equal angles at the centre
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Theorem 1 - Equal chords of a Circle Subtend Equal Angles at the Centre. Theorem 1: Equal chords of a circle (or of congruent circles)subtend equal angles at the centre
Given: AB and CD are equal chords of the same circle with center as O.
To prove: angle AOB = angle COD
Proof: In triangle AOB and triangle COD.
AO = CO (radii of the same circle)
AB = CD (given)
OB = OC (radii of the same circle)
Therefore triangle AOB is congruent to triangle COD by SAS congruence rule..
This implies angle AOB is equal to angle COD....
Hence proved...
Given: AB and CD are equal chords of the same circle with center as O.
To prove: angle AOB = angle COD
Proof: In triangle AOB and triangle COD.
AO = CO (radii of the same circle)
AB = CD (given)
OB = OC (radii of the same circle)
Therefore triangle AOB is congruent to triangle COD by SAS congruence rule..
This implies angle AOB is equal to angle COD....
Hence proved...
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