Question

prove that equal chords of a circle subtend equal angles at the centre?

Answer 1

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Given:  AB and CD are equal chords of the same circle with center as O.

To prove: angle AOB = angle COD

Proof: 

 In triangle AOB and triangle COD.             

AO = CO (radii of the same circle)             

AB = CD (given)           

 OB = OC (radii of the same circle)

Therefore triangle AOB is congruent to triangle COD

by SAS congruence rule..

This implies  angle AOB is equal to angle COD....                                       

Hence proved...

Answer 2

Hope it helps you dear.....❤❤