Question

Prove that equal chords of a circle subtend equal angles at the centre​

Answer 1

Answer:

In ΔAOB and ΔCOD,

AB=CD (Given)

AO=CO (radius)

OB=OD (radius)

By S.S.S congruency, ΔAOB≅ΔCOD

⇒∠AOB=∠COD.

solution

Answer 2

Answer:

$\huge\Large\underline\mathtt\pink{GiVeN:-}$

Circle with centre O

AB = CD  (chords of circle)

$\huge\Large\underline\mathtt\pink{To prove:-}$

∠AOB = ∠DOC

$\huge\Large\underline\mathtt\pink{Proof:-}$

In ΔAOB and ΔDOC

→ AO = OD               [Radius]

→ AB = CD               [Given]

→ OB = OC               [Radius]

→ΔAOB ≅ ΔDOC    [SSS congruence criteria]

→  ∠AOB = ∠DOC     [CPCT]

||Hᴇɴᴄᴇ Pʀᴏᴠᴇᴅ||

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