prove that equal chords of a circle subtend equal angles at the centre and it's converse
raminder1:
it's solution is already there in this app please search
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given : a circle c ( o, r) in which chord AB = chord CD
to prove: angle AOB = angle COD
proof: in triangle aob and triangle cod we have :
oa=oc [each equal to r ]
ob = od [ each equal to r ]
ab = cd [ given ]
so triangle aob congruent to triangle cod ( by SSS congruence )
hence angle aob = angle cod
to prove: angle AOB = angle COD
proof: in triangle aob and triangle cod we have :
oa=oc [each equal to r ]
ob = od [ each equal to r ]
ab = cd [ given ]
so triangle aob congruent to triangle cod ( by SSS congruence )
hence angle aob = angle cod
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see it was already there.....
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