Prove that equal chords of a circle subtend equal angles at the centre.
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In ΔAOB and ΔCOD,
AB=CD (Given)
AO=CO (radius)
OB=OD (radius)
By S.S.S congruency, ΔAOB≅ΔCOD
⇒∠AOB=∠COD.
Answered by
1
Answer:
In ΔAOB and ΔCOD,
AB=CD (Given)
AO=CO (radius)
OB=OD (radius)
By S.S.S congruency, ΔAOB≅ΔCOD
⇒∠AOB=∠COD.
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