Prove that equal chords of a circle subtend equal angles at the centre.
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❇️ Question :-
Prove that equal chords of a circle subtend equal angles at the centre.
❇️ Solution :-
✍️ Given :-
A circle with centre O, AB and AC are equal chords of circle.
- AB = AC
✍️ To prove :-
We have to prove that <AOB = <DOC
✍️ Proof :-
In ∆AOB and ∆AOC,
AO = OD [Radii]
AB = CD [Given]
OB=OC [Radii]
✍️ Therefore, by SSS rule, ∆AOB=~∆AOC.
<AOB = <DOC [CPCT]
✍️Hence, proved !!
_________________________________
All done :)
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