Question

prove that equal chords of circle subtend equal angle at centre​

Answer 1

Step-by-step explanation:

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Answer 2

Given :

• Circle with centre O
• AB = CD  (chords of circle)

To Prove :

∠AOB = ∠DOC

Proof :

In ΔAOB and ΔDOC

☞︎ AO = OD               [Radius]

☞︎ AB = CD               [Given]

☞︎ OB = OC               [Radius]

→  ΔAOB ≅ ΔDOC    [SSS congruence criteria]

→  ∠AOB = ∠DOC     [CPCT]

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