prove that equal chords of congruent circles subtend equal anglez at their centres
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first make a circle then make 2 chords AB AND CD O IS THE CENTRE now join the chords with the centre CO AND DO likewise BO AND AO we get 2 triangles THEN WE GET AB =CD GIVEN second AO=DO thirs BO= CO THEREFORE THE 2 triangles are equal therefore the 2 angles subtended by the chord are also equal in bracket cpct. Hope it helps.
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