prove that equal chords of congurent circles subted equal angles at the center
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In △AOB and △PXQ
AO=PX [Radius of congruent circles are equal]
∠AOB=∠PXQ [Given]
BO=QX [Radius of congruent circles are equal]
△AOB≅△PXQ [SAS congruence rule]
- ∴AB=PQ [CPCT]
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