Question

prove that equivalent resistance R is related with resistance R1 and R2 as the following when connected in parallel 1 by R equals to 1/R1+1/R2​

Answer 1

$\huge \mathcal \red{dear \: sanjeevegha}$

$\huge \mathcal \red{dear \: sanjeevegha}$For series

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel,

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R =

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 +

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21 R 2

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21 R 2

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21 R 2 = r 1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21 R 2 = r 1

$\huge \mathcal \red{dear \: sanjeevegha}$For seriesR 1 =r 1 +r 2 (equivalent resistance) for parallel, R = r1 + r 21 R 2 = r 1 +r 2

r 1

r 1

r 1 r 2

r 1 r 2

r 1 r 2

r 1 r 2

r 1 r 2 (equivalent resistance)

r 1 r 2 (equivalent resistance) ∴

r 1 r 2 (equivalent resistance) ∴ R 2

r 1 r 2 (equivalent resistance) ∴ R 2

r 1 r 2 (equivalent resistance) ∴ R 2

r 1 r 2 (equivalent resistance) ∴ R 2 R 1

r 1 r 2 (equivalent resistance) ∴ R 2 R 1

r 1 r 2 (equivalent resistance) ∴ R 2 R 1

r 1 r 2 (equivalent resistance) ∴ R 2 R 1 = r 1

r 1 r 2 (equivalent resistance) ∴ R 2 R 1 = r 1

r 1 r 2 (equivalent resistance) ∴ R 2 R 1 = r 1 r 2

r 1 r 2 (equivalent resistance) ∴ R 2 R 1 = r 1 r 2

r 1 r 2 (equivalent resistance) ∴ R 2 R 1 = r 1 r 2 (r 1 +r 2 ) 2

2

2

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