Question

prove that every cyclic quadrilateral Is rectangle.

Answer 1

Answer:

Step-by-step explanation:

ABCD is a rectangle.

<A = <B= <C = <D = 90 deg.

Since angle in a semicircle is 90 deg, A, B, C and D must be on the circumference of semicircles.

But AC=BD hence the semicircles must be the same, or the points A, B, C and D lie on a circle, hence ABCD is a cyclic quadrilateral.

Answer 2

Here is your answer


ABCD be a cyclic quadrilateral such that its diagonals AC and BD are the diameters of the circle through the vertices A, B, C, and D.


 Similarly, BD is a diameter.

 
  Therefore,  < ABC =
Thus, ABCD is a rectangle

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