Prove that every odd integer is of the form 4k+1 or 4k+3
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I think ur question is incomplete....
I think the question is every square or cube of odd integer is of the firm of 4k+1 or 4k+3
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Every odd integer is in the form 4k+1 or 4k+3
Step-by-step explanation:
The given numbers are 4k+1 or 4k+3.
Now, we know that when we multiply any number by an even number then the number becomes even number.
Since, 4 is an even number hence, 4k is an even number.
Now, when we add 1 or 3 to any even number then the number is odd.
Hence, when 1 or 3 is added to the even number 4k then the integers 4k +1 or 4k+3 is an odd integers.
#Learn More:
Prove that cube of any positive integer is of the form 4k,4k+1or4k+3,for some integer of k
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