Math, asked by santosh559, 1 year ago

Prove that every odd integer is of the form 4k+1 or 4k+3

Answers

Answered by sindhu69
4

I think ur question is incomplete....

I think the question is every square or cube of odd integer is of the firm of 4k+1 or 4k+3

Answered by SocioMetricStar
5

Every odd integer is in the form 4k+1 or 4k+3

Step-by-step explanation:

The given numbers are  4k+1 or 4k+3.

Now, we know that when we multiply any number by an even number then the number becomes even number.

Since, 4 is an even number hence, 4k is an even number.

Now, when we add 1 or 3 to any even number then the number is odd.

Hence, when 1 or 3 is added to the even number 4k then the integers 4k +1 or 4k+3 is an odd integers.

#Learn More:

Prove that cube of any positive integer is of the form 4k,4k+1or4k+3,for some integer of k

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