Prove that every positive integer is of the form 5n, 5n+1
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Step-by-step explanation:
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Let N be any positive integer.
On dividing N by 5 , Let M be Quotient and R be Remainder.
Then , By Euclid division lemma , we have
N = 5M+1 , where r = 0,1,2,3,4
N = 5M , where R = 0
N =5M + 1 , where R = 1
N = 5M + 2 , where R = 2
N = 5M + 3 , where R = 3
N = 5M + 4 , where R = 4
N = 5M , 5M+2 , 5M+4 are even values of N.
Thus
When N is odd , it is in the form of 5M , 5M+1 and 5M+3.
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