Question

prove that exterior angle of a triangle is equal to the sum of interior opposite angle

Answer 1

Answer:

Here is your answer!!

Answer 2

Answer:

✮requried answer:

$given :- \: A \: ∆ \: PQR \: , \: QR \: produced \\ \\ </p><p> where \: angle \: PRS \: exterior \: angles \: of \: ∆ PQR </p><p></p><p>To \: prove \: angle \: 4 = \: angle \: 1 \: + \: angle \: 2 \\ \\ </p><p></p><p>proof :- </p><p></p><p>angle \: 3 + \: angle \: 4= \: 180°( liner \: pair ) -------1 \\ \\ </p><p></p><p>in \: ∆ PQR \\ \\ </p><p></p><p>angle \: 1 \: + \: angle \: 2 \: + \: angle \: 3 \: = \: 180° \: ( angle \: sum \: property \: of ------- 2 \\ \\ </p><p></p><p></p><p>from \: 1 \: and \: 2 \: we \: get \\ \\ </p><p></p><p>angle \: 3+ \: angle \: 4= \: angle \: 1 \: + angle \: 2+ angle \: 3 \\ \\ </p><p></p><p>angle \: 4 \: = \: angle \: 1 \: + \: angle \: 2 \\ \\ </p><p></p><p>angle \: PRS \: = \: angle \: RPO \: + \: angle \: PQR \\ \\ </p><p></p><p> hence \: proved$