Question

prove that fast yll plz...

Answer 1

cosec^2A-cos^2Acosec^2A-1 =0
cosec^2A(1-cos^2A)=1
cosec^A ( sin^2A) =1
cosec^2A × 1/cosec^2A =1
as sin and cosec are reciprocal
LHS=RHS
Hence prooved
Hope it helps

Answer 2

Heya Friend !!

We need to prove that cosec^2A-cos^2A cosec^2A-1=0

Solution :-

Solving LHS ,
=> cosec^2A-cos^2A cosec^2A-1
{ Taking cosec^2A as common }
=> cosec^2A (1-cos^2A)-1
=> cosec^2A (sin^2A)-1
{ We know that 1-cos^2A=sin^2A and cosecA=1/sinA }
=> 1/sin^2A×sin^2A-1
=> 1-1
=> 0
=> RHS

Therefore , LHS=RHS .
Hence , proved .