prove that Fnet=T-m2g=m2a
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When the masses are equal, the pulley system is in equilibrium, i.e. balanced. When the masses are not equal, both masses will experience an acceleration (indicated with red arrows in Figure 1). ... m2a = T − m2g (2) where T is the tension in the string and g is the acceleration due to gravity (g = 9.8 m/s2).
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