Question

prove that following are irrational
7√5
​

Answer 1

Answer:

Let us assume that 7

5

is rational number

Hence 7

5

can be written in the form of

b

a

where a,b(b



=0) are co-prime

⟹7

5

=

b

a

⟹

5

=

7b

a

But here

5

is irrational and

7b

a

is rational

as Rational



=Irrational

This is a contradiction

so 7

5

is a irrational number