prove that following number irrational are √5
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Answer:
Yes this number is irrational because it is not in the form of p/q
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Answer:
√5
let √5 be rational or in the form of p/q where q not equals to 0 and p and q are co prime
√5=p/q ---(1)
squaring both side of (1)
5=p^2/q^2
q^2=p^2/5
therefore, 5 divides p^2
since, 5 divides p
5 is a factor of p
p=5 subsituiting p=5a
q^2=(5a)^2/5 =5×5a^2/5---(2)
q^2/5=a^2
therefore, 5 divides q^2
since, 5 divides q
5 is a factor of q
therefore, we can conclude 5 is a common factor of p and q
this contradiction has arisen due to our wrong asumption √5 is irrational not rational
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