Prove that for a cone made by rolling up a semicircle, the area of the curved surface is twice the base area.
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Area of one square pyramid = Area of square + Area of four triangles. = (256 + .... Prove that for a cone made by bending a semicircle, the curved surface area is double the base area.
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Answer:
Radius of the semicircle=R
Arc length=1/2×2πR=πR
Radius of the cone=r
Circumference of the cone=πr
2πr=πR
x=πR/2π=R/2
curved surface area of the cone=πrl=π×R/2×R{1/2πR²
Base area of the cone=πr²=π×(R/2)²
π×R²/4=1/4πR²
2×1/4πR²=1/2πR²
That means the curved surface area of the cone is twice it's base area.
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