prove that for all integers,if n square is even then n is even
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Answer:If n is even than it would be equal to 2k where k is any integer than n^2= 2k^2 . So 1 can be written as r= 2r which is an even number. Hence proved that if n is even than n^2 is even
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Explanation:
If n is even than it would be equal to 2k where k is any integer than n^2= 2k^2 . So 1 can be written as r= 2r which is an even number. Hence proved that if n is even than n^2 is even …
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