Prove that for all single digit prime numbers, p, p3 + p is a multiple of 10
Answers
Step-by-step explanation:
(i) Prove that for all single digit prime numbers, P, p3 + p is a multiple of 10 (ii) Show, using algebra, that for n e N (n + 1)? – n' is not a multiple of 3
SOLUTION
TO DETERMINE
Prove that for all single digit prime numbers, p, p³ + p is a multiple of 10
EVALUATION
Here the given expression is p³ + p
Now all single digit prime numbers are 2 , 3 , 5 , 7
When p = 2 we have
p³ + p
= 2³ + 2
= 8 + 2
= 10 : which is a multiple of 10
When p = 3 we have
p³ + p
= 3³ + 3
= 27 + 3
= 30 : which is a multiple of 10
When p = 5 we have
p³ + p
= 5³ + 5
= 125 + 5
= 130 : which is a multiple of 10
When p = 7 we have
p³ + p
= 7³ + 7
= 343 + 7
= 350 : which is a multiple of 10
Hence proved
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