Question

Prove that for an integer m, every even number is of the form 2m.

Answer 1

Answer:

We know that, even integers are 2, 4, 6,… So, it can be written in the form of 2m. a = 2m + r, where a ≤ r < 2 i.e.,r = 0 and r = 1. when, a = 2m for some integer m, then clearly a is even.

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