Question

prove that for any four consecutive terms of an arithmetic sequence the sum of the two terms on the two ends and the sum of the two terms​

Answer 1

Answer:

Let the smallest term be a and the common difference be d.

Then the four consecutive terms are a, a+d, a+2d and a+3d.

The two terms on the end sum up to a+(a+3d) = 2a+3d and the two terms in the middle sum up to (a+d)+(a+2d)=2a+3d. Hence they are the same.

Step-by-step explanation:

Answer 2

Answer:

see the attchment pic.. hope it helps u