Question

Prove that for any positive integer n, n³-n is divisible by 6.​

Answer 1

Answer:

Out of three (n – 1), n, (n + 1) one must be even, so a is divisible by 2. 2. (n – 1) , n, (n + 1) are consecutive integers thus as proved a must be divisible by 3. Thus, n³ – n is divisible by 6 for any positive integer n.

Step-by-step explanation:

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