Prove that for any value of ' a ' the given polynomial expression a^2-3a+19 is not divisible by 289 PLEASE SOLVE THIS . IT'S URGENT! !
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solution:
Here,
D= b^2 - 4ac
= (-3)^2 - 4*1*19
= 9 - 76
= -67 [<0]
Hence, a has no real value.
,if we a has no real value, then it can't devide 289.
______________
Hope you get it☺
#Amrit⭐
Here,
D= b^2 - 4ac
= (-3)^2 - 4*1*19
= 9 - 76
= -67 [<0]
Hence, a has no real value.
,if we a has no real value, then it can't devide 289.
______________
Hope you get it☺
#Amrit⭐
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