Question

Prove that for any value of ' a ' the given polynomial expression a^2-3a+19 is not divisible by 289 PLEASE SOLVE THIS . IT'S URGENT! !

Answer 1

solution:

Here,

D= b^2 - 4ac

= (-3)^2 - 4*1*19

= 9 - 76

= -67 [<0]

Hence, a has no real value.

,if we a has no real value, then it can't devide 289.

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#Amrit⭐