Prove that for finite change in vvolume In (V2/V1) = alpha (T2-T1)
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Answer:
dT = 0 so dU = and dH =
q = –w
w = – nRT ln
V2
V1
P2V2 = P1 V1 or
V2
V1
=
P1
P2
w = – nRT ln
P1
P2
Adiabatic Reversible Expansion
ñq = so dU = ñw = – P dV
dU = – P dV or dU = Cv dT
Cv dT = – P dV
Cv
dT
T
= – nR
dV
V
⌡
⌠
T1
T2Cv
dT
T
= – ⌡
⌠
V1
V2
nR
dV
V
Cv ln T |
T2
T1
= – nR ln V |
V2
V1
Cv ln
T2
T1
= – nR ln
V2
V1
Method 1:
Cv
nR ln
T2
T1
= – ln
V2
V1
c = Cv/nR
T2
T1
Cv/nR
=
V1
V2
or V2T
Cv/nR
2
= V1T
Cv/nR
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