Question

prove that



\frac{ \sin \: a \tan \: a }{1 - \cos \: a} = 1 + \sec \: a
1−cosa
sinatana
​
=1+seca

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Answer 1

Answer:

$\frac{ \sin \: a \: \tan \: a }{1 - \cos \: a } = \frac{ { \sin \: a }^{2} }{ \cos \: a \: (1 - \cos \: a) } \\ = \frac{1 - { \cos}^{2} \: a}{ \cos \: a \: ( 1 - \cos \: a) } \\ = \frac{1 + \cos \: a }{ \cos \: a } \\ = \frac{ \sin \: a \: \tan \: a }{1 - \cos \: a} = 1 + \sec \: a \:$

hence proved

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Answer 2

Answer:

hence your question will be proved