Question

prove that

\frac{ \sin \: a \tan \: a }{1 - \cos \: a} = 1 + \sec \: a 1−cosasinatana =1+seca

no spam ❌❌❌​​

Answer 1

Answer:

$\frac{ \sin \: a \: \tan \: a }{1 - \cos \: a } = \frac{ { \sin \: a }^{2} }{ \cos \: a \: (1 - \cos \: a) } \\ = \frac{1 - { \cos}^{2} \: a}{ \cos \: a \: ( 1 - \cos \: a) } \\ = \frac{1 + \cos \: a }{ \cos \: a } \\ = \frac{ \sin \: a \: \tan \: a }{1 - \cos \: a} = 1 + \sec \: a \:$

hence proved

hope it helps you ✅✅✅

Answer 2

Answer:

your answer is in the attachment