prove that function f:R-R given by f(x)=2x, is one-one and onto
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f(x)=2x
one -one
f(x1)=2x1
f(x2)=2x2
putting
f(x1)=f(x2)
2x1=2x2
x1=x2
hence if f(x1)=f(x2), x1=x2
therefore function f is one -one
onto,
f(x)=2x
let f(x)=y, such that y€R
2x=y
x=y/2
since y is a real number,
h3nce y/2 will also be a real number so, x will also bea real number, i.e,. x€R
hence, f is onto
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