Question

prove that g 1 2 3 4 5 6 is a finite abelian group of order 6 under addition modulo 7.

Answer 1

Answer:

Not a  Group because identity element 0 is not an element of the group

Step-by-step explanation:

As you know all the addition group have 0 as identity

without identity element group property not satisfied hence it is not a group .

counter example as

6+1=7 and operation is mod 7 so you get =0

but 0 is not the element of group hence disprove