Prove that General term in the expansion of ( +1/2)^13is 13 ^13−2r. Hence
find the 12th term.
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Answered by
1
Answer:
39
Step-by-step explanation:
ANSWER
13
th
term of the expansion (x
2
+
x
2
)
n
is given by
n
C
12
(x
2
)
n−12
(
x
2
)
12
The coefficient of x in the term can be written as 2n−24−12
Since the term is independent of x,2n−36=0
⇒n=18
The divisors of 18 are 1,2,3,6,9,18
Sum of these divisors is 1+2+3+6+9+18=39
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