prove that : Given question
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sin10°sin30°sin50°sin70°
⟹cos80°cos60°cos40°cos20°
⟹12(cos20°cos40°cos80°)
⟹12(2sin20°cos20°)cos40°cos80°2sin20°
⟹14(2sin40°cos40°)cos80°2sin20°
⟹182sin80°cos80°2sin20°
⟹116sin160°sin20°
sin(180°−θ)=sinθ
⟹sin10°sin30°sin50°sin70°=116
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