Question

Prove that Gravitational acceleration g = 9.81 m/sec​

Answer 1

Answer:

It has an approximate value of 9.81 m/s2, which means that, ignoring the effects of air resistance, the speed of an object falling freely near the Earth's surface will increase by about 9.81 metres (32.2 ft) per second every second. ...

Answer 2

Answer:

brother first of all value of g is 9.81 m/s2 not 9.81 m/s

Explanation:

Mathematically the equation for g is:

g = G *Me/ r2..............(1)

g = acceleration due to gravity (units m/s2)

G = the universal gravitational constant, G = 6.673 x 10-11N·m2kg2

Me = mass of a large body (for example, Earth). The mass of the Earth is 5.98x 1024 kg.(10 to the 24 power)

r = the distance from the center of mass of the large body. The radius of the Earth is 6.38 x 106 m (10 to the 6 power)

now put these values in equation (1)

we get g = 9.81 m/s2.