Math, asked by shijasal, 10 months ago

prove that group of order 3 is cyclic ​

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Answered by mayank681753
1

Answer:

Prove that if H is a group of order 3, then H is cyclic. Solution: If H is a group with |H| = 3, then H = {1H, a, b}. Consider the element ab. ... Therefore a2 = b and we see that H = {1, a, a2} = 〈a〉 is cyclic.

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