Question

Prove that: h = u2/2g

Answer 1

Answer:

Since the body is thrown upwards, the formula we will be using is

$v^{2} = {u}^{2} - 2gh$

since it is negative acceleration or against the gravity

Explanation:

${v}^{2} = {u}^{2} - 2gh \\ 0 = {u }^{2} - 2gh \\ 2gh = {u}^{2} \\ h = \frac{u^{2} }{2g}$

Here v square = 0 because final velocity = 0

Answer 2

Answer:

Concept:

Gravitational acceleration will be negative because it is against gravity.

Explanation:

upward motion:

$v^{2}=u^{2}-2 g h \begin{aligned}&v^{2}=u^{2}-2 g h \\&0=u^{2}-2 g h \\&2 g h=u^{2} \\&h=\frac{u^{2}}{2 g}\end{aligned}$

Hence Proved.

#SPJ2