Question

prove that (i^1)+(i^2)+(i^3)+(i^4)= 0 where i=iota

Answer 1

i = $\sqrt{-1}$ = $\sqrt{-1}$
$i^{2}$= -1 
$i^{3}$= -1($\sqrt{-1}$) = -$\sqrt{-1}$
$i^{4}$= (-1)(-1)= 1
hence the sum = 0