prove that (i) 4+5√2 (ii)3√3-7 are irraitional
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9To prove that the number (4−5√2) is an irrational number, we have to prove that the number (4−5√2) is not a rational number. ... Hence, our assumption that 4−5√2 is a rational number is wrong. Therefore, (4−5√2) is an irrational number. Hence proved.
Therefore there exists no rational number r such that r2=3. Hence the root of 3 is an irrational number.
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