Question

prove that i^-4k+3 =-i
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Answer 1

Answer:

$\displaystyle i^{-4k+3}\\= i^{-4k}\times i^3\\= (i^2)^{-2k}\times i^2\times i\\=\bigl((-1)^2\bigr)^{-k}\times(-1)\times i\\=1^{-k}\times -i\\=1\times -i\\=-i$