prove that (I+Cot A+tan A) (Sin A-cos A) = Sin A tan A-Cot A COSA
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Answer:
Let
L.H.S= (1+cotA+tanA)(sinA−cosA)
=(1+sinAcosA+cosAsinA)(sinA−cosA)
=(sinAcosAsinAcosA+cos2A+sin2A)(sinA−cosA)
=(1+sinAcosA)(sinAcosAsinA−cosA)
Now,
R.H.S=sinAtanA−cotAcosA
=sinAcosAsinA−sinAcosAcosA
=cosAsin2A−sinAcos2A
=sinAcosAsin
Step-by-step explanation:
I hope it will be help you
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