prove that √i+√-i=√2
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Answered by
15
Let the values of "i" be 1.
Squaring the left hand side, we get :
(√i)^2 + (√-i)^2
= i + i
= 1+1
=2 .
Therefore, √i + √-i = √2 (proved)
Squaring the left hand side, we get :
(√i)^2 + (√-i)^2
= i + i
= 1+1
=2 .
Therefore, √i + √-i = √2 (proved)
Answered by
34
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