prove that :i¹⁰⁴+i¹⁰⁹+i¹¹⁴+i¹¹⁹=0x
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Answered by
3
Answer:
LHS * 0 = 0
RHS * 0 = 0
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Answered by
2
Step-by-step explanation:
we know
i²=-1
i³= -i
i⁴=1
therefore i¹⁰⁴ = 1
i¹⁰⁹ = i¹⁰⁸*i = i
i¹¹⁴= i¹¹²*i²= -1
i¹¹⁹= i¹¹⁶*i³= -i
therefore adding these four, we get 0
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