prove that if 9^m×3^2×(3-^m/2) ^-2-27n/3^3m×2^3=1/27 then m-n=1.
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Answer:
(3
m
.2)
3
9
n
.3
2
.3
n
−(27)
n
=3
−3
⇒
(3
m
.2)
3
9
n
.3
2
.3
n
−(27)
n
=3
−3
⇒
3
3m
.2
3
3
3n
.3
2
−3
3n
=
3
3
1
⇒
3
3
m×8
3
3n
(3
2
−1)
=
3
3
1
⇒
3
3
m×8
3
3n
×8
=
3
3
1
⇒
3
3(m−n)
1
=
3
3−1
1
⇒m−n=1 (proved)
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