Prove that, if A and B and C and D are positive nationals such that a + b root b equal to 3 + root 3 then either equal to C and B equal to D or b and D are squares of rationals
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Given a + √b = c + √d
Case (i): Let a=c
⇒ a + √b = c + √d becomes
a + √b = a + √d
⇒ √b = √d
∴ b = d
Case (ii): Let a ≠ c
Let us take a = c + k where k is a rational number not equal to zero.
⇒ a + √b = c + √d becomes
(c + k) + √b = c + √d
⇒ k + √b = √d
Let us now square on both the sides,
⇒ (k + √b)2 = (√d)2
⇒ k2 + b + 2k√b = d
⇒ 2k√b = d – k2 – b
Notice that the RHS is a rational number.
Hence √b is a rational number
This is possible only when b is square of a rational number.
Thus d is also square of a rational number as k + √b = √d
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