prove that if a and b are both odd integers, then ab+1 is an even integer
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If a and b are both odd then
a = 2m + 1 and
b = 2n + 1 for some integers m and n.
Then their product ab = (2m + 1)(2n + 1)
= 4mn + 2m + 2n + 1
= 2(2mn + m + n) + 1
and 2mn + m + n is an integer.
So if a and b are both odd, their product ab is odd. It follows that if ab is even, either a or b (or both) must be even.
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Answer:
prove that if a and b are both odd integers, then ab+1 is an even integer
If a and b are both odd then
a = 2m + 1 and
b = 2n + 1 for some integers m and n.
Then their product ab = (2m + 1)(2n + 1)
= 4mn + 2m + 2n + 1
= 2(2mn + m + n) + 1
and 2mn + m + n is an integer.
So if a and b are both odd, their product ab is odd. It follows that if ab is even, either a or b (or both) must be even.
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