Question

Prove that if a, b and c are
angles of a triangle, then sec(a+c/2)= cosec (b/2)​

Answer 1

Step-by-step explanation:

a+b+c=180

a+c=180-b

sec(a+c/2)=sec((180-b) / 2)=sec(90- b/2)=cosec(b/2)