Question

prove that if a+b+c=0 then a^3+b^3+c^3=3abc​

Answer 1

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A+B+C=0

WE HVE TO FIND

a³+b³+c³=3abc

PROOF

WHEN WE FACTORIES

a³+b³+c³-3abc= (a+b+c)(a²+b²+c²-ab-bc-ac)

PUT THE VALUE OF a+b+c=0

Thn we get

a³+b³+c³-3abc= (0)(a²+b²+c²-ab-bc-ac)

a³+b³+c³=3abc

Hence,proved

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Answer 2

Answer:

a3 + b3 + c3 = 3 abc

Step-by-step explanation:

a3 +b3 + c3 - 3abc = (a+b+c) (a2 + b2 +c2-ab-bc-ac)

a3 + b3 +c3 -3 abc= 0 * (a2 + b2 + c2 -ab-bc-ca) (a+b+c=0)

a3 + b3 + c3 - 3 abc = 0

therefore, a3+b3+c3 = 3abc