Math, asked by MrMustafa, 5 months ago

prove that if a+b+c=0 then, a³+b+³c³=3abc
for a= -10, b= 6, c= 4.​

Answers

Answered by eshanirfangill
1

Answer:

prove is 10+6-4

ans 10+6= 16

16 +(-4)

16-4=12

Follow me

is that 12 is the prove

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