Physics, asked by temporarygirl, 5 months ago

Prove that if a body is thrown vertically upward, the time of ascent is equal to the time of descent.

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Answers

Answered by apal9991
1

Let,

u = Initial velocity

v = Final velocity

h = Height attained

a = acceleration

t = time

Ascent:

Ball thrown upward with velocity u So,v=0 at maximum height h. Also a=−g

Now, using v=u+at

0=u−gt

a

t

a

=

g

u

.....1

Where t

a

= time of ascent

Also , by using v

2

=u

2

+2as

0=u

2

−2gh

u=

2gh

........2

From equation 1 and 2 , we get ,

t

a

=

g

2h

.......A

Descent :

Ball comes down from height h , So , u=0 and a=g .

So , using v=u+at

v=gt

d

.........3

Where t

d

= Time of descent

Now , using v

2

=u

2

+2as

v

2

=0+2gh

v=

2gh

..........4

From equations 3 and 4 , we get ,

t

d

=

g

2h

.....B

From equations A and B , we see that t

a

=td

Sry if you can't understand

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Hope it helps

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Answered by snehaprajnaindia204
6

Google answer dekhe bujhi jibu

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