Question

prove that if a body is thrown vertically upwards,then the time of ascent is equal to the time of descent.
plz tell me how is it ??

Answer 1

Time of Ascent
The time taken by body thrown up to reach Maximum height h is called as time of Ascent.
Let t1 be time of Ascent at maximum height, it's velocity is zero,
V=0
Hence, V=u-gt
0=u-gt1
t1=u/g---------(1)
Time of descent:
After reaching the maximum height, the body begins to travel downwards and reaches the ground.
The time taken to by a freely falling body to touch the ground is called time of descent.
Intial velocity for downward journey is zero, u=0
Let t2 be time of descent.
s=ut +1/2 gt2
h=0+1/2gt2²
t2=√2h/g
but, h=u/2g
so, we get
t2 =√2u²/2g
=u/g---------(2)
from equation 1 and 2 we can say
t1=t2
The time of Ascent is equal to time descent in the case of bodies moving under gravity.
Hope this helps you friend
Thanks ✌️ ✌️