prove that if a line is drawn parallel to one side of a triangle to intersects the other two sides in distance points the other two sides are divided in the same ratio (please sir/mam ) send me solution...
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Step-by-step explanation:
Given:
DE∣∣BC
To prove that:
EC/AE=BD/AD
Proof:
∠AED=∠ACB Corresponding angles
∠ADE=∠ABC Corresponding angles
∠EAD is common to both the triangles
ΔAED∼ΔACB by AAA similarity
AC/AE=AB/AD
AE+EC/AE=AD+BD/AD
EC/AE=BD/AD
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