Question

prove that if a line is drawn parallel to one side of a triangle to intersects the other two sides in distance points the other two sides are divided in the same ratio (please sir/mam ) send me solution...​

Answer 1

Step-by-step explanation:

Given:

DE∣∣BC

To prove that:

EC/AE=BD/AD

Proof:

∠AED=∠ACB Corresponding angles

∠ADE=∠ABC Corresponding angles

∠EAD is common to both the triangles

ΔAED∼ΔACB by AAA similarity

AC/AE=AB/AD

AE+EC/AE=AD+BD/AD

EC/AE=BD/AD